Hi Ismail,
I have just taken a quick look and I would have presumed it would have been properties of GetCurrent() such as:

umbraco.presentation.nodeFactory.Node.GetCurrent().Path
umbraco.presentation.nodeFactory.Node.GetCurrent().Id
umbraco.presentation.nodeFactory.Node.GetCurrent().CreateDate

As all of the above examples are attributes in the XML cache along with level, so it is strange that it is missing.

Warren :)

Doesn't look like it.

You could use split path on the comma, and count how many levels it is?

umbraco.presentation.nodeFactory.Node.GetCurrent().Path.Split(',').Length
Matt

Warren,

Yup thats what i thought it should be there anyhow got round it i did

var nodeAsXml = umbraco.library.GetXmlNodeById(CurrentNode.Id.ToString());
var nodeLevel = nodeAsXml.Current.GetAttribute("level", "");

Regards

Ismail

How strange that Level is missing as a property in the Node class.

I'd go with Matt's suggestion of splitting the Path and getting the count/length.

Interesting alternatives on StackOverflow... http://stackoverflow.com/questions/541954/how-would-you-count-occurences-of-a-string-within-a-string-c

Seems the foreach is fastest! ;-)

string path = umbraco.presentation.nodeFactory.Node.GetCurrent().Path;
int count = 0;
foreach (char c in path)
  if (c == ',') count++;

Anyway, we're talking milliseconds here... still interesting to a geek like me! ;-)

Cheers, Lee.

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